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How do you solve #2 m + n = 0# and #m - 5 n = 22# using substitution?

Answer 1

Genesis Allen

#n=-22/6=-11/3, m=-11/6#

#2m+n=0# #2m=-n# #m-5n=22# #-n-5n=22# #-6n=22# #n=-22/6=-11/3# #m=-11/6#

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Answer 2

Hazel Anglin

To solve the system of equations 2m + n = 0 and m - 5n = 22 using substitution, first solve one of the equations for one variable in terms of the other variable. Then, substitute this expression into the other equation and solve for the remaining variable. Finally, substitute the value found back into one of the original equations to solve for the other variable.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.