How do you solve #-2(d+6)=-10#?

Answer 1

#color(green)(d=-1#

#-2(d+6)=-10#
#-2d-12=-10# #-2d=-10+12# #-2d=2# #color(green)(d=-1#
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Answer 2

To solve -2(d + 6) = -10, you first distribute -2 across (d + 6), then solve for d.

-2(d + 6) = -10 -2d - 12 = -10 -2d = -10 + 12 -2d = 2 d = 2 / -2 d = -1

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Answer 3

To solve the equation -2(d + 6) = -10:

  1. Start by distributing the -2 across the parentheses: -2 * d - 2 * 6 = -10

  2. Simplify both sides of the equation: -2d - 12 = -10

  3. Add 12 to both sides to isolate the variable term: -2d - 12 + 12 = -10 + 12 -2d = 2

  4. Divide both sides by -2 to solve for d: (-2d)/(-2) = 2/(-2) d = -1

Therefore, the solution to the equation -2(d + 6) = -10 is d = -1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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