How do you solve #2 cos^2 ø  cos ø = 0#?
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To solve the equation (2 \cos^2 \theta  \cos \theta = 0), we can factor out a common term of (\cos \theta):
[ \cos \theta (2\cos \theta  1) = 0 ]
Now we solve for the values of (\theta) that make each factor equal to zero:

(\cos \theta = 0)

(2\cos \theta  1 = 0)
Solving (1) gives us:
[ \cos \theta = 0 ]
This occurs at (\theta = \frac{\pi}{2} + \pi n) and (\theta = \frac{\pi}{2} + \pi n), where (n) is an integer.
Solving (2) gives us:
[ 2\cos \theta  1 = 0 ]
[ 2\cos \theta = 1 ]
[ \cos \theta = \frac{1}{2} ]
This occurs at (\theta = \frac{\pi}{3} + 2\pi n) and (\theta = \frac{\pi}{3} + 2\pi n), where (n) is an integer.
So, the solutions to (2 \cos^2 \theta  \cos \theta = 0) are:
[ \theta = \frac{\pi}{2} + \pi n, \frac{\pi}{2} + \pi n, \frac{\pi}{3} + 2\pi n, \frac{\pi}{3} + 2\pi n ]
where (n) is an integer.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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