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How do you solve #2(c + 15) = 4c + 3 #?

Answer 1

Nathan Axel

#c=27/2#

#2(c+15)=4c+3#

#2c+30=4c+3#

#2c-4c=3-30#

#-2c=-27 //*(-1)#

#2c=27#

#c=27/2#

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Answer 2

Isaiah Anthony

First, distribute the 2 on the left side to get 2c + 30. Then, subtract 2c from both sides to isolate the variable term on one side. This yields 30 = 2c + 3. Next, subtract 3 from both sides to get 27 = 2c. Finally, divide both sides by 2 to solve for c, which gives you c = 13.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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