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How do you solve #2( - 6x + 9) = - 66#?

Answer 1

Savannah Anderson

#x=7#

#2(- 6x+9) = -66#

First distribute the 2 to #-6x and 9#

#-12x+18 = -66#

Then Subtract #18# from both sides

#-12x= -84#

And lastly, divide by #-12#

#x = 7#

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Answer 2

Nathan Axel

#x=7#

#1.# First, distribute the #2# into the #(-6x+9)# by first multiplying the #2# by #-6x# and then by #9# to get #-12x+18#

#-12x+18=-66#

#2.# Then, since #18# does not have an #x# with it, you can subtract 18 from both sides of the equation, taking away the #18# from the left side and subtracting #18# from #-66# as well.

This makes sure that both sides of the equals sign are equal. When you solve equations like this, always try to look for ways to get the #x# term alone on one side. So, by doing this step, you have

#-12x=-84#

#3.# Look for ways to isolate #x# again. This is an easy one since #x# is just multiplied by #-12#. Divide both sides by #-12# to get #x=7#.

#(-12x)/(-12) = (-84)/(-12)#

#x=7#

I hope this was helpful! :)

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Answer 3

Jameson Allen

To solve the equation 2(-6x + 9) = -66, first distribute the 2:

2(-6x + 9) = -66 -12x + 18 = -66

Then, subtract 18 from both sides:

-12x = -84

Finally, divide both sides by -12:

x = 7

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.