How do you solve #2-6lnx=10#?

Answer 1

Work it like a normal algebra problem to get ln x on one side. Then use a calculator or log tables.

The calculations are the same as for any algebraic equation up until you reach the real logarithm.

# 2 − 6xxln(x) = 10# ; #-6ln(x) = 8# ; #ln(x) = -(4/3)#

NOW, we calculate the inverse, exponential, or antilog of each side:

#e^(ln(x)) = e^(-(4/3))# ; # x = 0.264#
CHECK: # 2 − 6xxln(x) = 10# ; # 2 − 6ln(0.264) = 10#
# 2 − 6(-1.33) = 10# ; # 2 - (-8) = 10# ; #10 = 10# CORRECT!
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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