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How do you solve #2/5x=3# by clearing the fractions?

Answer 1

Isaiah Anthony

See a solution process below:

First, multiply each side of the equation by #color(red)(5)# to clear the fractions and keep the equation balanced:

#color(red)(5) xx 2/5x = color(red)(5) xx 3#

#cancel(color(red)(5)) xx 2/color(red)(cancel(color(black)(5)))x = 15#

#2x = 15#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = 15/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 15/2#

#x = 15/2#

#x = 7.5#

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Answer 2

Jace Anderson

To solve the equation 2/5x = 3 by clearing the fractions, you can multiply both sides of the equation by the denominator of the fraction, which is 5. This will eliminate the fraction. So, 5 * (2/5x) = 5 * 3. After multiplying, you get 2x = 15. Finally, divide both sides by 2 to isolate x. Therefore, x = 15/2 or x = 7.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.