How do you solve # -2 < 4z + 10 ≤ 12#?

Answer 1

#-2<4z+10<=12# Subtract 10 from all the 3 members: #-2-10<4z+10-10<=12-10# #-12<4z<=2# Devide by 4 all the three members: #-3< z <=1/2# That's all folks!

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Answer 2

Savannah Anderson

To solve the inequality -2 < 4z + 10 ≤ 12, you first subtract 10 from all parts of the inequality to isolate 4z. This gives you -12 < 4z ≤ 2. Then, you divide each part by 4 to solve for z, resulting in -3 < z ≤ 0.5. So, the solution for z is -3 < z ≤ 0.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve # -2 &lt; 4z + 10 ≤ 12#?

How do you solve # -2 < 4z + 10 ≤ 12#?