# How do you solve #2/(3y-4)=5/(6y-7)#?

by cross multiplying:

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To solve the equation 2/(3y-4)=5/(6y-7), you can cross-multiply. Multiply the numerator of the first fraction (2) by the denominator of the second fraction (6y-7), and multiply the numerator of the second fraction (5) by the denominator of the first fraction (3y-4). This gives you the equation 2(6y-7) = 5(3y-4). Simplify both sides of the equation by distributing and combining like terms. Solve for y by isolating the variable on one side of the equation.

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