Home > Algebra > Clearing Denominators in Rational Equations

How do you solve #2/(3y-4)=5/(6y-7)#?

Answer 1

Eli Assouline

# 2 / (3y -4) = 5/ (6y -7)#

by cross multiplying:

# 2 xx (6y -7) = 5 xx (3y -4)#

# 12y - 14 = 15y -20#

# -3y = -6#

# y = 2#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Abigail Allen

To solve the equation 2/(3y-4)=5/(6y-7), you can cross-multiply. Multiply the numerator of the first fraction (2) by the denominator of the second fraction (6y-7), and multiply the numerator of the second fraction (5) by the denominator of the first fraction (3y-4). This gives you the equation 2(6y-7) = 5(3y-4). Simplify both sides of the equation by distributing and combining like terms. Solve for y by isolating the variable on one side of the equation.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.