How do you solve #-2/3x+3<11#?

Answer 1

#x > -12#

#- 2/3 x + 3 < 11#
subtract #3# to both sides #- 2/3 x + 3 - 3 < 11 - 3 #
#- 2/3 x < 8 #
bescause the coefficient of #x# is -ve value, change the position to become +ve value. # -8 < 2/3 x #
multiply both sides with #3/2# # -8 * 3/2 < 2/3 x * 3/2 #
#-12 < x# or #x > -12#
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Answer 2

To solve the inequality (-\frac{2}{3}x + 3 < 11):

  1. Subtract 3 from both sides to isolate the term with the variable: (-\frac{2}{3}x < 8)

  2. Multiply both sides by (-\frac{3}{2}) to solve for (x). Since you're multiplying by a negative number, remember to reverse the inequality sign: (x > -12)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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