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How do you solve #2(3b-4)=8b-11#?

Answer 1

#b=3/2#

You start multiplying #2# times the bracket: #6b-8=8b-11# Take all the #bs# on the left and the numbers on the right changing sign when moving them: #6b-8b=8-11# add: #-2b=-3# take #-2# to the right: #b=(-3)/-2=3/2#

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Answer 2

Julia Adams

To solve the equation 2(3b - 4) = 8b - 11, follow these steps:

Distribute the 2 on the left side of the equation: 6b - 8 = 8b - 11.
Move all the b terms to one side of the equation and the constants to the other side: Subtract 6b from both sides: -8 = 2b - 11.
Add 11 to both sides of the equation: 3 = 2b.
Divide both sides by 2 to isolate b: b = 3/2 or b = 1.5.

Therefore, the solution to the equation is b = 1.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.