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How do you solve #2/3 x+2>4#?

Answer 1

Abigail Allen

Re-arrange the equation such that you get x by itself, such that the equation forms #x gt 3#

First, move the 2 to the right hand side by subtracting 2 from both sides:

#2/3x > 2#

Next, multiply both sides by the inverse of the fractional coefficient:

#2/3x*(3/2) > 2*(3/2) rArr color(red)(x > 3)#

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Answer 2

Jace Anderson

To solve ( \frac{2}{3}x + 2 > 4 ), follow these steps:

Subtract 2 from both sides to isolate the term containing ( x ): [ \frac{2}{3}x > 4 - 2 ] [ \frac{2}{3}x > 2 ]
Multiply both sides by ( \frac{3}{2} ) to get rid of the fraction: [ \frac{3}{2} \times \frac{2}{3}x > 2 \times \frac{3}{2} ] [ x > 3 ]

So, the solution to the inequality is ( x > 3 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #2/3 x+2&gt;4#?

How do you solve #2/3 x+2>4#?