# How do you solve #(-2/3)x^2 + (-4/3)x + 1 = 0# by completing the square?

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To solve the quadratic equation (-2/3)x^2 + (-4/3)x + 1 = 0 by completing the square, follow these steps:

- Divide the entire equation by the coefficient of ( x^2 ), which is (-2/3), to make the coefficient of ( x^2 ) equal to 1.
- Rewrite the equation in the form ( x^2 + bx + c = 0 ).
- Complete the square by adding ((b/2)^2) to both sides of the equation.
- Factor the perfect square trinomial on the left side of the equation.
- Solve for ( x ) by taking the square root of both sides and isolating ( x ).
- Simplify the radical expression if necessary to obtain the solutions.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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