How do you solve #2-3(x+2)<11#?

Answer 1

#x > -5#

Treat inequalities in the same way as an equation, unless you multiply or divide by a negative number, in which case the inequality sign will change around.

#2-3(x+2)<11" remove brackets"#
#2-3x-6 <11" the x-term is negative"#
Either:#color(white)(.........................................)# Or
#color(red)(-4-11 <3x) color(white)(................................)color(blue)(-3x <11-2+6)#
#color(red)(-15 <3x)" "div 3color(white)(...................)color(blue)(-3x < 15)#
#color(red)(-5 < x)color(white)(.............................................) color(blue)((-3x)/(-3)>15/(-3))" "div -3#
#color(red)(rArr x > -5)color(white)(.........................................) color(blue)(x> -5)#
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Answer 2

To solve 2 - 3(x + 2) < 11, first distribute the -3 across the expression inside the parentheses, then combine like terms, and isolate the variable x by performing the necessary operations.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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