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How do you solve #2(3 - a) - (-2)(a - 3) = - (3a - 2)#?

Answer 1

#a=2/3#

The first step is to multiply out to get rid of the brackets, remembering that multiplying a negative by a negative gives a positive. #2(3-a)-(-2)(a-3)=-(3a-2)#

#=6-2a-(-2a+6)=-3a+2#

#=6-2a+2a-6 = -3a+2#

Move all the items to the left hand side, remembering to change the sign.

#=6-2a+2a-6+3a-2=0#

Group the items.

#-2a+2a+3a+6-6-2=0#

#:.3a-2=0#

#3a=2#

#a=2/3#

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Answer 2

Isaiah Anthony

First, distribute the terms inside the parentheses: 2(3 - a) becomes 6 - 2a, and (-2)(a - 3) becomes -2a + 6. Then, simplify the equation: 6 - 2a - (-2a + 6) = - (3a - 2). After simplifying both sides, the equation becomes: 6 - 2a + 2a - 6 = -3a + 2. Next, combine like terms: -2a and 2a cancel out, leaving 0 on the left side. So, the equation simplifies to 0 = -3a + 2. Finally, solve for 'a': 3a = 2, and a = 2/3. Therefore, the solution is a = 2/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.