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How do you solve #-2/3(6/5x - 7/10) = 17/20#?

Answer 1

Genesis Allen

#x=-23/48#

Multiply both sides of the equation by #-3/2# The equation becomes #(6/5 x- 7/10) = 17/20 xx -3/2# #6/5x-7/10=-51/40#

Add #7/10# to both sides #6/5x = -51/40 + 7/10#

Find common denominator to add fractions: #6/5x = -51/40 + 28/40#

#6/5x=-23/40#

Multiply both sides by reciprocal of #6/5# #x=-23/40 xx 5/6#

#x=-23/48#

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Answer 2

Savannah Anderson

To solve the equation -2/3(6/5x - 7/10) = 17/20, first distribute the -2/3 to both terms inside the parentheses. Then solve for x.

-2/3 * 6/5x = -12/15x -2/3 * -7/10 = 14/30

So, the equation becomes: -12/15x + 14/30 = 17/20.

Next, combine like terms:

-12/15x + 14/30 = 17/20 -12/15x + 14/30 - 17/20 = 0

Now, find a common denominator for all fractions, which is 60:

-48x/60 + 28/60 - 51/60 = 0

Combine the fractions:

(-48x + 28 - 51)/60 = 0

Simplify:

-48x - 23/60 = 0

Now, isolate x:

-48x = 23/60

Divide both sides by -48:

x = (23/60) / -48

x = 23/60 * -1/48

x = -23/2880

So, the solution is x = -23/2880.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.