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How do you solve #2/3-1/6#?

Answer 1

Julian Avila

Make them both have the same denominator.

So make them both have #6# on the bottom. Then change #2/3# into a denominator of #6# so

#3 xx 2 = 6#

#2 xx 2 = 4#

So it is now

#2/3 = 4/6#

Subtract #1/6# from #4/6# to basically get #4-1#, which is #3#, and keep the denominator the same. The answer is #3/6#, which simplified is #1/2#

#4/6 - 1/6 = (4-1)/6 = 3/6 = 1/2#

Hope you get it :)

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Answer 2

Riley Anderson

To solve ( \frac{2}{3} - \frac{1}{6} ), first find a common denominator for the fractions, which is 6. Then, rewrite each fraction with the common denominator:

( \frac{2}{3} = \frac{2 \times 2}{3 \times 2} = \frac{4}{6} )

( \frac{1}{6} ) remains the same.

Now, subtract the fractions:

( \frac{4}{6} - \frac{1}{6} = \frac{4 - 1}{6} = \frac{3}{6} )

Finally, simplify the fraction:

( \frac{3}{6} = \frac{1}{2} )

So, ( \frac{2}{3} - \frac{1}{6} = \frac{1}{2} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.