How do you solve #19- \frac { 5} { 2} x = 34#?

Answer 1

#x=-6#

The fraction might be what's bothering you here. Luckily, we can multiply all terms by #2# to get rid of it. We now have
#38-5x=68#
Since I did the same thing to both sides of this equation, I didn't change the value of this equation. Let's subtract #38# from both sides to get
#-5x=30#
And our last step would be to divide both sides by #-5# to get
#x=-6#

Hope this helps!

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

#x=-6#

One possible way is to change to a decimal:

#5/2 rArr 2.5#
#therefore# #19-2.5x=34#
#-2.5x=15#
#x=15/-2.5=-6#

Alternate (although harder):

Change everything to a fraction:

#38/2-5/2x=68/2#
(multiply all numbers by #2# and divide by #2#)
#-5/2x=30/2#
#x=(30/2)/(-5/2)=-6#

Another alternate way:

Multiply all by #2#
#38-5x=68#
#-5x=30#
#x=30/-5=-6#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 3

To solve the equation (19 - \frac{5}{2}x = 34), follow these steps:

  1. Subtract 19 from both sides of the equation to isolate the variable term: [19 - 19 - \frac{5}{2}x = 34 - 19]

  2. Simplify: [-\frac{5}{2}x = 15]

  3. Multiply both sides of the equation by (-\frac{2}{5}) to solve for (x): [\left(-\frac{2}{5}\right) \cdot \left(-\frac{5}{2}\right)x = \left(-\frac{2}{5}\right) \cdot 15]

  4. Simplify: [x = -\frac{2}{5} \cdot 15]

  5. Calculate: [x = -\frac{30}{5}]

  6. Simplify: [x = -6]

So, the solution to the equation is (x = -6).

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7