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How do you solve #19 < 7 + 1/3k + 2 -2/3k#?

Answer 1

Eva Adamson

Solve #19<7+1/3k+2-2/3k# .

Combine like terms.

#19<7+2+1/3k-2/3k# =

#19<9-1/3k#

Simplify #1/3k# to #k/3#.

#19<9-k/3#

Multiply both sides times #3#.

#19*3<9*3-k# =

#57<27-k#

Subtract #27 from both sides.

#57-27<27-27-k# =

#30<-k#

Multiply both sides times #-1#. This will cause the inequality to be reversed.

#-30>k#

Flip to get #k# on the left side.

#k<-30#

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Answer 2

Abigail Allen

To solve the inequality 19 < 7 + 1/3k + 2 - 2/3k, you can follow these steps:

Combine like terms on the right side of the inequality: 19 < 9 - 1/3k
Subtract 9 from both sides to isolate the term involving k: 10 < -1/3k
Multiply both sides by -3 to get rid of the fraction and flip the inequality sign: -30 > k

So, the solution to the inequality is k < -30.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #19 &lt; 7 + 1/3k + 2 -2/3k#?

How do you solve #19 < 7 + 1/3k + 2 -2/3k#?