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How do you solve #18x^2-50=0#?

Answer 1

Hazel Anglin

#x=+-5/3#

#"add 50 to both sides"#

#rArr18x^2=50#

#"divide both sides by 18"#

#rArrx^2=50/18=25/9#

#color(blue)"take the square root of both sides"#

#rArrx=+-sqrt(25/9)larrcolor(blue)"note plus or minus"#

#rArrx=+-5/3#

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Answer 2

Eli Assouline

To solve the equation 18x^2 - 50 = 0, you can use the quadratic formula, which states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

For the equation 18x^2 - 50 = 0, a = 18, b = 0, and c = -50. Substituting these values into the quadratic formula:

x = (-0 ± √((0)^2 - 4 * 18 * (-50))) / (2 * 18)

Simplify inside the square root:

x = (± √(0 + 3600)) / 36

x = ± √3600 / 36

x = ± √100 / 6

x = ± 10 / 6

Therefore, the solutions are:

x = 10/6 and x = -10/6, which simplifies to x = 5/3 and x = -5/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.