How do you solve #16x^2 - 9 = 0# by factoring?

Answer 1

See explanation

It is #16x^2-9=0=>(4x)^2-3^2=0=>(4x-3)*(4x+3)=0=> x=3/4 or x=-3/4#

Remarks

We used the identity #a^2-b^2=(a-b)*(a+b)#
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Answer 2

To solve the equation (16x^2 - 9 = 0) by factoring, you can use the difference of squares formula. It states that (a^2 - b^2 = (a + b)(a - b)). Applying this formula to the given equation, we have:

[16x^2 - 9 = (4x)^2 - 3^2 = (4x + 3)(4x - 3)]

Setting each factor equal to zero, we get:

[4x + 3 = 0 \implies 4x = -3 \implies x = -\frac{3}{4}]

[4x - 3 = 0 \implies 4x = 3 \implies x = \frac{3}{4}]

So, the solutions are (x = -\frac{3}{4}) and (x = \frac{3}{4}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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