How do you solve #16x^2 - 9 = 0# by factoring?
See explanation
It is #16x^2-9=0=>(4x)^2-3^2=0=>(4x-3)*(4x+3)=0=> x=3/4 or x=-3/4#
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To solve the equation (16x^2 - 9 = 0) by factoring, you can use the difference of squares formula. It states that (a^2 - b^2 = (a + b)(a - b)). Applying this formula to the given equation, we have:
[16x^2 - 9 = (4x)^2 - 3^2 = (4x + 3)(4x - 3)]
Setting each factor equal to zero, we get:
[4x + 3 = 0 \implies 4x = -3 \implies x = -\frac{3}{4}]
[4x - 3 = 0 \implies 4x = 3 \implies x = \frac{3}{4}]
So, the solutions are (x = -\frac{3}{4}) and (x = \frac{3}{4}).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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