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How do you solve #16x^2 - 64=0#?

Answer 1

Kennedy Adams

#color(blue)(x = +-2#

#16x^2 - 64=0#

Taking out the common term #(16)#: #16(x^2 - 4)=0# #x^2 - 4=0# #x^2 =4# # x = sqrt4# #color(blue)(x = +-2#

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Answer 2

Jameson Allen

To solve (16x^2 - 64 = 0), you first add 64 to both sides to get (16x^2 = 64), then divide both sides by 16 to get (x^2 = 4). Finally, take the square root of both sides to find the solutions: (x = \pm 2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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