# How do you solve #(16-x^2)/(x^2-9)>=0#?

Identify points and intervals at which this is satisfied to find solution:

#x in [-4, -3) uu (3, 4]#

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First, find the critical points by setting the numerator and denominator equal to zero. Then, test the intervals created by the critical points to determine where the inequality is satisfied. The solutions are (x\leq -4, -3\leq x \leq 3, x\geq 4).

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