How do you solve #16 = t + 7#?

Answer 1

#t = 9#

To find the value of #t#, you must get #t# on one side of the equals sign and all of the other numbers in the other side.
To cancel out #+7# from the right side of the sum, minus #7# from both side of the sum. To get the right answer, you must do whatever you do on one side of the equals sign to the other side of the equals sign.
#16 - 7 = t#
#16 - 7# is equal to #9# so:
#9 = t#

Or this is more commonly written like:

#t = 9#
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Answer 2

To solve for t:

16 - 7 = t

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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