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How do you solve #-16>=5(2z-11)# and graph the solution on a number line?

Answer 1

Savannah Anderson

#3.9>=z or z<=3.9#

graph{x<=3.9 [-14.24, 14.24, -7.12, 7.12]}

#-16>=5(2z-11)#

#=> -16>=(5*2z)+(5*-11)#

#=> -16>=10z+(-55)#

#=> -16>=10z-55#

#=> -16+55>=10z#

#=> 39>=10z#

#=> 39/10>=z#

#=> 3.9>=z or z<=3.9#

graph{x<=3.9 [-14.24, 14.24, -7.12, 7.12]}

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Answer 2

Kennedy Adams

To solve the inequality -16 ≥ 5(2z - 11), you would first distribute the 5 on the right side, then combine like terms, and isolate the variable ( z ). Once you find the value of ( z ), you can represent the solution on a number line.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #-16&gt;=5(2z-11)# and graph the solution on a number line?

How do you solve #-16>=5(2z-11)# and graph the solution on a number line?