How do you solve #16-3q=10#?

Answer 1

#q=2#

#"isolate "-3q" by subtracting 16 from both sides"#
#cancel(16)cancel(-16)-3q=10-16#
#-3q=-6#
#"divide both sides by "-3#
#(cancel(-3) q)/cancel(-3)=(-6)/(-3)rArrq=2#
#color(blue)"As a check"#
#"left side "=16-(3xx2)=16-6=10=" right side"#
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Answer 2

#q= 2#

Distributive Property is Used.

#16 - 3q = 10#
Subtracting #16# from both sides;
#16 - 3q - 16 = 10 - 16#
#16 - 16 - 3q = 10 - 16#
#0 - 3q = -6#
#-3q = -6#
Dividing both sides by the coefficient of #q;#
#(-3q)/(-3) = (-6)/(-3)#
#(cancel(-3)q)/cancel(-3) = (cancel-6)/(cancel-3)#
#q = 6/3#
#q= 2#
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Answer 3

To solve the equation 16 - 3q = 10, first subtract 16 from both sides to isolate the term with 'q'. This gives you -3q = -6. Then, divide both sides by -3 to solve for 'q'. This yields q = 2. So, the solution to the equation is q = 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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