How do you solve #16-2n-5+8n=65#?

Answer 1

#n = 9#

#16 - 2n - 5 + 8n = 65#
First, color-code the like terms on the left hand side: #color(red)(16) quadcolor(green)(-quad2n) quadcolor(red)(-quad5) quadcolor(green)(+quad8n) = 65#
Combine the like terms: #11 + 6n = 65#
Subtract #color(blue)11# from both sides: #11 + 6n quadcolor(blue)(-quad11) = 65 quadcolor(blue)(-quad11)#
#6n = 54#
Now divide both sides by #color(blue)6#: #(6n)/color(blue)6 = 54/color(blue)6#
Therefore, #n = 9#

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Answer 2

To solve the equation 16 - 2n - 5 + 8n = 65, follow these steps:

  1. Combine like terms on both sides of the equation.
  2. Add or subtract terms to isolate the variable term (in this case, n) on one side of the equation.
  3. Solve for the variable by performing the necessary operations.

Here's a step-by-step breakdown:

16 - 2n - 5 + 8n = 65

Combine like terms: (16 - 5) + (-2n + 8n) = 65 11 + 6n = 65

Isolate the variable term (6n): Subtract 11 from both sides: 11 - 11 + 6n = 65 - 11 6n = 54

Solve for n: Divide both sides by 6: 6n / 6 = 54 / 6 n = 9

Therefore, the solution to the equation is n = 9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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