Home > Algebra > Clearing Denominators in Rational Equations

How do you solve #-15z + 20z + 5z - - 4z = - 14#?

Answer 1

Eli Assouline

#z = - 7/22#

#15z + 20z + 5z - - 4z = - 14#

Before simplifying, note that #- -# is same thing as #+ (- xx - = +)#

#15z + 20z + 5z + 4z = - 14#

#44z = -14#

Divide both sides by #44#

#(44z)/44 = (-14)/44#

#cancel(44z)/cancel44 = (-14)/44#

#z = - cancel(14)^7/cancel(44)^22#

#z = - 7/22#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Hazel Anglin

To solve the equation ( -15z + 20z + 5z - (-4z) = -14 ), first simplify the expression on the left side of the equation by combining like terms:

[ -15z + 20z + 5z + 4z = -14 ] [ (-15 + 20 + 5 + 4)z = -14 ] [ 14z = -14 ]

Then, divide both sides of the equation by 14:

[ z = \frac{-14}{14} ]

Finally, simplify:

[ z = -1 ]

So, the solution to the equation is ( z = -1 ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.