How do you solve #15y - \frac { 11} { 2} = \frac { 11} { 2} y + 2#?

Answer 1

You can save yourself some trouble and a possible source of error by multiplying everything by #2#

#->30y-11=11y+4#
Now move the #y#'s to one side, and the numbers to the other, by subtracting #11y# from both sides and adding #11#:
#->30y-cancel11-11y+cancel11=cancel(11y)+4-cancel(11y)+11#
#->19y=15->y=15/19#
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Answer 2

#y=15/19#

#"to eliminate the fractions multiply ALL terms by 2 the"# #"denominator of the fractions"#
#(2xx15y)-(cancel(2)^1xx11/cancel(2)^1)=(cancel(2)^1xx(11y)/cancel(2)^1)+(2xx2)#
#rArr30y-11=11y+4larrcolor(red)" no fractions"#
#"subtract 11y from both sides"#
#30y-11y-11=cancel(11y)cancel(-11y)+4#
#rArr19y-11=4#
#"add 11 to both sides"#
#19ycancel(-11)cancel(+11)=4+11#
#rArr19y=15#
#"divide both sides by 19"#
#(cancel(19) y)/cancel(19)=15/19#
#rArry=15/19#
#color(blue)"As a check"#

Substitute this value into the equation and if left side equals right side then it is the solution.

#"left "=(15xx15/19)-11/2=225/19-11/2=241/38#
#"right "=(11/2xx15/19)+2=165/38+2=241/38#
#rArry=15/19" is the solution"#
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Answer 3

To solve the equation ( 15y - \frac{11}{2} = \frac{11}{2}y + 2 ), you can follow these steps:

Step 1: Move all terms involving ( y ) to one side of the equation and the constant terms to the other side. You can do this by adding or subtracting terms as necessary. In this case, let's subtract ( \frac{11}{2}y ) from both sides and add ( \frac{11}{2} ) to both sides:

[ 15y - \frac{11}{2} - \frac{11}{2}y = 2 + \frac{11}{2} ]

Step 2: Simplify both sides of the equation:

[ 15y - \frac{11}{2} - \frac{11}{2}y = 2 + \frac{11}{2} ] [ (15y - \frac{11}{2}y) = (2 + \frac{11}{2}) ]

Step 3: Combine like terms:

[ (\frac{15}{2}y) = (\frac{25}{2}) ]

Step 4: Now, isolate ( y ) by dividing both sides of the equation by ( \frac{15}{2} ):

[ y = \frac{\frac{25}{2}}{\frac{15}{2}} ]

Step 5: Simplify the expression:

[ y = \frac{25}{2} \times \frac{2}{15} ] [ y = \frac{25}{15} ]

Step 6: Simplify the fraction:

[ y = \frac{5}{3} ]

So, the solution to the equation is ( y = \frac{5}{3} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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