# How do you solve #15x^(-2)+7x^(-1)-2=0#?

Multiply through by

Rearranging the terms gives us a familiar quadratic form.

This gives

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To solve the equation 15x^(-2) + 7x^(-1) - 2 = 0:

- Multiply the entire equation by x^2 to clear the denominators.
- Rearrange the equation to standard form.
- Use the quadratic formula to solve for x.
- Substitute the values of a, b, and c into the quadratic formula and simplify.

The solutions will be the values of x that make the equation true.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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