How do you solve #15g+18>13g-2>=6+15g#?

Answer 1

#-10 < g ≤ -4#

Do

#i) \ 15g + 18 > 13g - 2 #
#15g - 13g > -18 - 2#
#2g > -20#
#g > -10#

and

#ii) \ 13g-2 ≥ 6 + 15g#
#13g - 15g ≥ 2 + 6#
#-2g ≥ 8#
#g ≤ -4 -># [division by a negative number = sign change]
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Answer 2

To solve the inequality 15g + 18 > 13g - 2 ≥ 6 + 15g, follow these steps:

  1. Solve the leftmost inequality: 15g + 18 > 13g - 2

    Subtract 13g from both sides: 15g - 13g + 18 > -2

    Simplify: 2g + 18 > -2

    Subtract 18 from both sides: 2g + 18 - 18 > -2 - 18

    Simplify: 2g > -20

    Divide both sides by 2: 2g/2 > -20/2

    Simplify: g > -10

  2. Solve the rightmost inequality: 13g - 2 ≥ 6 + 15g

    Subtract 13g from both sides: 13g - 13g - 2 ≥ 6 + 15g - 13g

    Simplify: -2 ≥ 6 + 2g

    Subtract 6 from both sides: -2 - 6 ≥ 6 + 2g - 6

    Simplify: -8 ≥ 2g

    Divide both sides by 2: -8/2 ≥ 2g/2

    Simplify: -4 ≥ g

  3. Combine the solutions: -4 ≥ g > -10

Therefore, the solution to the inequality is -4 ≥ g > -10.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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