How do you solve #-15c+7c+1=3-8c#?

Answer 1

See the solution process below:

By combining like terms, we can rewrite the equation's left side as follows:

#-8c + 1 = 3 - 8c#
We can now add #color(red)(8c)# to each side of the equation to eliminate this common term:
#color(red)(8c) - 8c + 1 = 3 - 8c + color(red)(8c)#
#0 + 1 = 3 - 0#
However, #1 != 3#

Consequently, there isn't a fix for this issue.

Or

The solution is the empty or null set: #{O/}#
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Answer 2

To solve the equation -15c + 7c + 1 = 3 - 8c, you would first combine like terms on both sides of the equation. Then, you would isolate the variable term by moving all terms involving c to one side and constant terms to the other side. Here's the step-by-step process:

  1. Combine like terms: -15c + 7c = -8c -8c + 1 = 3 - 8c

  2. Move the variable terms to one side and the constant terms to the other side: -8c + 8c = 3 - 1

  3. Combine like terms: 0 = 2

Since the equation simplifies to 0 = 2, it means there is no solution for c that satisfies the equation. Therefore, the equation has no solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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