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How do you solve #15>= 8 + b - 12#?

Answer 1

#b<=19#

Treat inequalities in the same way as equations, except if you multiply or divide by a negative number, then the inequality sign has to change around.

#" "15 >=8 + b- 12#

#15+12-8 >=b#

#" "19 >=b#

This is easier written as #b<=19#

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Answer 2

Savannah Anderson

To solve ( 15 \geq 8 + b - 12 ), you first add 12 to both sides:

( 15 + 12 \geq 8 + b - 12 + 12 )

This simplifies to:

( 27 \geq 8 + b )

Then, subtract 8 from both sides:

( 27 - 8 \geq 8 + b - 8 )

Which simplifies to:

( 19 \geq b )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #15&gt;= 8 + b - 12#?

How do you solve #15>= 8 + b - 12#?