How do you solve #15=2m+3#?
Step 1: Subtract 3 from each side of the equation to keep it balanced:
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To solve the equation 15 = 2m + 3, first, subtract 3 from both sides to isolate the term with the variable: 15 - 3 = 2m. This simplifies to 12 = 2m. Then, divide both sides by 2 to solve for m: 12 ÷ 2 = 2m ÷ 2. This gives you m = 6. So, the solution to the equation is m = 6.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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