How do you solve #14^(x+1) = 36#?
Take the logarithm of each side. A logarithm rule lets us take the exponent outside of the logarithm.
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To solve the equation (14^{x+1} = 36), you can follow these steps:

Take the natural logarithm (ln) of both sides of the equation to eliminate the exponential term: [ \ln(14^{x+1}) = \ln(36) ]

Use the property of logarithms that allows you to bring the exponent down as a coefficient: [ (x+1) \ln(14) = \ln(36) ]

Divide both sides of the equation by ( \ln(14) ) to isolate ( x + 1 ): [ x + 1 = \frac{\ln(36)}{\ln(14)} ]

Finally, subtract 1 from both sides to solve for ( x ): [ x = \frac{\ln(36)}{\ln(14)}  1 ]
You can calculate the approximate value of ( x ) using a calculator.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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