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How do you solve #13x + 26 < 65#?

Answer 1

#x <3#

What I would do is subtract 26 to both sides of the expression to cancel out the 26 on the left side and to get 13x by itself like this:

#13x + 26 < 65# # -26 -26#

When you do that you should get

#13x < 39#

Now divide both sides by 13 to get x by itself like this:

#(13x)/13 < 39/13#

When you do that division you're left with x on the left hand side and 3 on the right hand side, with a less than sign separating them like this:

#x <3#

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Answer 2

Jameson Allen

To solve the inequality 13x + 26 < 65:

Subtract 26 from both sides to isolate the term with x: 13x < 65 - 26 13x < 39
Divide both sides by 13 to solve for x: x < 39 / 13 x < 3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #13x + 26 &lt; 65#?

How do you solve #13x + 26 < 65#?