How do you solve #13= \frac { 4- b } { 3}#?

Question

Genesis Allen · Accepted Answer

#b=-35# Multiply by #3#: #(13xx3)=(4-b)/cancel3# #rArr 39=4-b# Bring the #b# to the other side to make is positive: #b+39=4# #rArr b=-35#

Kennedy Adams · Answer

#b = -35#

As per the question, we have

#13 = (4 - b)/3#

#13# x #3 = (4 - b)/3# x #3# ... [Multiplying 3 on both the sides]

#:.39 = (4 - b)/cancel3# x #cancel3#

#:. 39 = 4 - b#

#:.39 - 4 = 4 - 4 - b# ... [Subtracting 4 from both the sides]

#:.35 = cancel4 cancel-4 - b#

#:. - b = 35#

#:. b = -35#

Hence, the answer.

Savannah Anderson · Answer

#b=-35#

#"multiply both sides by 3"#

#3xx13=cancel(3)xx(4-b)/cancel(3)#

#39=4-b#

#"subtract 4 from both sides"#

#39-4=cancel(4)cancel(-4)-b#

#35=-b" or "b=-35#

#color(blue)"As a check"#

Substitute this value into the right side of the equation and if equal to the left side then it is the solution.

#(4-(-35))/3=(4+35)/3=39/3=13#

#b=-35" is the solution"#

Ethan Adkins · Answer

undefined To solve for $b$ in the equation $13 = \frac{4-b}{3}$, follow these steps:

1. Multiply both sides by 3 to get rid of the denominator:
$$3 \times 13 = 4 - b$$
$$39 = 4 - b$$

2. Subtract 4 from both sides to isolate $-b$:
$$39 - 4 = 4 - 4 - b$$
$$35 = -b$$

3. Multiply both sides by -1 to solve for $b$:
$$b = -35$$

So, $b = -35$.

Eva Abramson · Answer

undefined To solve the equation $13 = \frac{4 - b}{3}$, follow these steps:

1. Multiply both sides of the equation by 3 to eliminate the fraction:
$$13 \times 3 = \frac{4 - b}{3} \times 3$$

2. Simplify:
$$39 = 4 - b$$

3. Now, isolate the variable $b$ by subtracting 4 from both sides of the equation:
$$39 - 4 = 4 - b - 4$$
$$35 = -b$$

4. Finally, solve for $b$ by multiplying both sides by -1:
$$-1 \times 35 = -b \times -1$$
$$-35 = b$$

So, the solution to the equation is $b = -35$.