How do you solve #13-4x=1-x#?

Answer 1

#x = 4#

To solve an equation you need to have the variables on one side and the numbers on the other. In order to keep the variable positive, move them to the right side.

#13-4x=1-x" "larr# add +4x to both sides
#13-4xcolor(red)(+4x)=1-xcolor(red)(+4x)#
#13color(blue)(-1)= 1+3xcolor(blue)(-1)" "larr# subtract 1 from each side
#12 = 3x" "larrdiv3# to isolate x
#12/3 = (3x)/3#
#4=x" "larr# this is the solution
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Answer 2

To solve the equation 13 - 4x = 1 - x:

  1. Move the variable terms to one side by adding x to both sides: 13 - 4x + x = 1 - x + x

  2. Simplify the equation: 13 - 3x = 1

  3. Move the constant terms to one side by subtracting 13 from both sides: 13 - 3x - 13 = 1 - 13

  4. Simplify the equation: -3x = -12

  5. Divide both sides by -3 to solve for x: -3x / -3 = -12 / -3

  6. Simplify: x = 4

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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