How do you solve #13-3p=-5(3+2p)#?

Answer 1

#:. p = -4#

Here are the steps to solve the question stated.

#13-3p = -5(3+2p)#

First, open the brackets.

#=> 13 - 3p = -15 -10p#
Note that the -ve sign of the number #5#, has to be multiplied by both #3# and #2p# which makes #2p# and #3# become -ve as well.

Then, categorize the same terms together.

#=> 13 + 15 = 3p - 10p#
#=> 28 = -7p#
#:. p = -4#
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Answer 2

To solve the equation 13 - 3p = -5(3 + 2p), first distribute the -5 to the terms inside the parentheses to get 13 - 3p = -15 - 10p. Then, add 10p to both sides and add 15 to both sides to isolate the variable term, resulting in 13 + 15 = -3p + 10p. Simplify both sides to get 28 = 7p. Finally, divide both sides by 7 to solve for p, giving you p = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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