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How do you solve #12x + 3 = 6x + 3#?

Answer 1

Isaiah Anthony

#x=0#

Place the constants on one side and all the variables on the other.

We get #12x-6x=3-3#

#6x=0#

So, #x=0#

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Answer 2

Eva Abramson

#color(magenta)(x=0#

#12x+3=6x+3#

#12x-6x=3-3#

#6x=0#

#x=0/6#

#color(magenta)(x=0#

To double-check:

#12x+3=6x+3#

#12(0)+3=6(0)+3#

#0+3=0+3#

#color(red)(3=3#

Hence it is proved that #x=0#

I hope this is helpful.

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Answer 3

Jace Anderson

To solve the equation 12x + 3 = 6x + 3, you need to isolate the variable x. Subtract 6x from both sides of the equation to move all terms involving x to one side. This yields 6x = 0. Then, divide both sides by 6 to solve for x. So, x = 0.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.