How do you solve #-12x^2 + 5x +2=0# using the quadratic formula?
The quadratic formula is
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You can solve the equation -12x^2 + 5x + 2 = 0 using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = -12, b = 5, and c = 2.
Substituting these values into the formula:
x = (-5 ± √(5^2 - 4(-12)(2))) / (2(-12))
Calculate:
x = (-5 ± √(25 + 96)) / -24 x = (-5 ± √121) / -24 x = (-5 ± 11) / -24
So the solutions are:
x1 = (-5 + 11) / -24 = 6 / -24 = -1/4 x2 = (-5 - 11) / -24 = -16 / -24 = 2/3
Therefore, the solutions to the equation -12x^2 + 5x + 2 = 0 are x = -1/4 and x = 2/3.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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