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How do you solve #12x^2=48x#?

Answer 1

Hazel Anglin

Shown below

Rearrange:

#12x^2-48x =0 #

Factor out the #x#:

#x(12x-48) = 0 #

Hence product of two polynomials equaling 0 means

#x = 0 #

and

#12x - 48 = 0 #

#12x = 48 => x= 48/12 #

#x = 0 # and # x= 4 #

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Answer 2

Hazel Anglin

To solve the equation 12x^2 = 48x, first, subtract 48x from both sides to get:

12x^2 - 48x = 0

Next, factor out the common factor of 12x:

12x(x - 4) = 0

Set each factor to zero and solve for x:

12x = 0 => x = 0

x - 4 = 0 => x = 4

So, the solutions to the equation are x = 0 and x = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.