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How do you solve #128/-g<4#?

Answer 1

#g in (-oo , -32)#
or
#g in ]-oo,-32[#

I'm assuming that you want to find the values of g.

So you start by multiplying both sides by -1 which gives #128/g > -4# then taking the inverse of both sides. #g/128 < -1/4# then multiplying both sides by 128. #g< -32#

so #g in (-oo , -32)#

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Answer 2

Hazel Anglin

To solve the inequality 128/-g < 4:

Multiply both sides of the inequality by -g (since dividing by a negative number reverses the inequality sign): 128 > -4g
Divide both sides by -4: -32 < g

So, the solution to the inequality is -32 < g.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #128/-g&lt;4#?

How do you solve #128/-g<4#?