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How do you solve #12/(y+5) + 1/2 = 2#?

Answer 1

Eva Abramson

#12/(y+5)+1/2=2#

#12/(y+5)=2-1/2#

#12/(y+5)=3/2#

*Cross multiply

#12(2)=3(y+5)#

#24=3y+15#

#3y=24-15#

#3y=9#

#1/3 * 3y =1/3 * 9#

#y=3#

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Answer 2

Julia Adams

To solve the equation 12/(y+5) + 1/2 = 2, you can follow these steps:

Start by subtracting 1/2 from both sides of the equation: 12/(y+5) = 2 - 1/2
Simplify the right side of the equation: 12/(y+5) = 3/2
To eliminate the fraction, multiply both sides of the equation by (y+5): (y+5) * 12/(y+5) = (y+5) * 3/2
Simplify the left side of the equation: 12 = 3(y+5)/2
Multiply both sides of the equation by 2 to get rid of the fraction: 2 * 12 = 3(y+5)
Simplify the left side of the equation: 24 = 3(y+5)
Distribute the 3 on the right side of the equation: 24 = 3y + 15
Subtract 15 from both sides of the equation: 24 - 15 = 3y
Simplify the left side of the equation: 9 = 3y
Divide both sides of the equation by 3 to solve for y: 9/3 = y
Simplify the left side of the equation: 3 = y

Therefore, the solution to the equation 12/(y+5) + 1/2 = 2 is y = 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.