How do you solve #12<8x<=7 #?
the other hand
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To solve the inequality ( 12 < 8  x \leq 7 ), you can start by isolating ( x ) by performing operations to both sides of the inequality.

Subtract 8 from all parts of the inequality: [ 12  8 < 8  x  8 \leq 7  8 ] [ 20 < x \leq 15 ]

To get rid of the negative sign in front of ( x ), you need to multiply all parts of the inequality by 1. When you multiply or divide by a negative number, you must reverse the inequality signs. [ 1(20) > 1(x) \geq 1(15) ] [ 20 > x \geq 15 ]
So, the solution to the inequality is ( 15 \leq x < 20 ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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