How do you solve # -12<6+2a<8 #?

Answer 1

#-9 < a < 1.#

Given that #-12<6+2a<8#
Adding #-6#, #-12-6<-6+6+2a<-6+8,# i.e., #-18<2a<2.#
Now we multiply the inequality by#1/2,# noting that #1/2# being #+ve#, its order will not be changed.
Hence, #-18*1/2<2a*1/2<2*1/2, rArr -9 < a < 1.#,
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Answer 2

To solve the compound inequality -12 < 6 + 2a < 8, first subtract 6 from all parts of the inequality. Then divide each part by 2 to isolate 'a'. This results in -9 < 2a < 1. Finally, divide each part by 2, yielding -4.5 < a < 0.5. So, the solution to the compound inequality is -4.5 < a < 0.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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