How do you solve #|12- 5x | < 22#?

Answer 1

#-2 < x< 34/5#

#|12-5x|<22# means
either #12-5x<22# i.e.
#12-22<5x# i.e.
#5x> -10# i.e. #x> -2#
or #-(12-5x)<22# i.e.
#-12+5x<22# i.e.
#5x< 22+12# i.e. #5x<34# i.e. #x<34/5#
Hence either #x> -2# or #x< 34/5#, which can be combined as
#-2 < x< 34/5#
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Answer 2

#-2 < x< 34/5#

This can be interpreted as

#-5x+12<22# and #-5x+12> -22#
We can subtract #12# from both sides in both inequalities to get
#-5x<10# and #-5x> -34#
Next, we can divide both sides by #-5#. Recall the direction of the inequality will flip. We get
#x> -2# and #x< 34/5#

We can combine these to get

#-2 < x < 34/5#

Hope this helps!

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Answer 3

To solve the inequality (|12 - 5x| < 22):

  1. Split the inequality into two cases: a. (12 - 5x < 22) b. (-(12 - 5x) < 22)

  2. Solve each case separately: a. For (12 - 5x < 22): (12 - 5x < 22) (-5x < 22 - 12) (-5x < 10) (x > -2)

    b. For (-(12 - 5x) < 22): (-(12 - 5x) < 22) (12 - 5x > -22) (-5x > -22 - 12) (-5x > -34) (x < 6.8)

  3. Combine the solutions from both cases: (x > -2) and (x < 6.8)

So, the solution to the inequality (|12 - 5x| < 22) is (-2 < x < 6.8).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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