How do you solve #12 = 2x^2 - 5x#?
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To solve the equation 12 = 2x^2 - 5x:
- Rearrange the equation to set it equal to zero: 2x^2 - 5x - 12 = 0.
- Factor the quadratic equation: (2x + 3)(x - 4) = 0.
- Set each factor equal to zero and solve for x: 2x + 3 = 0, which gives x = -3/2. x - 4 = 0, which gives x = 4.
- The solutions to the equation are x = -3/2 and x = 4.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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