How do you solve #12 – 2x <16 #?

Answer 1

#x < -2#

#12-2x<16# Subtract 12 from both sides: #12-2x-12<16-12# Which gives the following: #-2x< 4# Now divide both side by -2: #-2x/-2<4/-2# Which gives the following: #x<-2#

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Answer 2

Eli Assouline

To solve 12 - 2x < 16:

Subtract 12 from both sides: -2x < 16 - 12
Simplify: -2x < 4
Divide both sides by -2 (remembering to reverse the inequality when dividing by a negative number): x > -2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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How do you solve #12 – 2x &lt;16 #?

How do you solve #12 – 2x <16 #?