How do you solve #12/21= (x-5)/x#?

Answer 1

#x = 105/9 or 11(6)/9 or 11(2)/3#

#12/21 = (x-5)/x#
Cross multiply to eliminate the denominators. #12(x) = (x-5)21#
Use distributive property to eliminate the ( ). #12x = 21x - 105#
Combine like terms. #12x - 21x = cancel(21x) - cancel(21x) - 105#
#-9x = -105#
Divide by the coefficient to isolate the variable. #(cancel(-9)x)/cancel(-9) = -105/-9#
#x = 105/9 or 11(6)/9 or 11(2)/3#
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Answer 2

To solve the equation 12/21 = (x-5)/x, you can cross-multiply. Multiply 12 by x and 21 by (x-5), then set the two products equal to each other. Simplify the equation and solve for x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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